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2736x^2+88200x+1826=0
a = 2736; b = 88200; c = +1826;
Δ = b2-4ac
Δ = 882002-4·2736·1826
Δ = 7759256256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7759256256}=\sqrt{576*13470931}=\sqrt{576}*\sqrt{13470931}=24\sqrt{13470931}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88200)-24\sqrt{13470931}}{2*2736}=\frac{-88200-24\sqrt{13470931}}{5472} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88200)+24\sqrt{13470931}}{2*2736}=\frac{-88200+24\sqrt{13470931}}{5472} $
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